Soal Dan Kunci Jawaban Matematika Kelas 8 Semester 2 Halaman 29, Table Triple Pythagoras

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Diketahui kalau soal dan jawaban mengenai tabel triple Pythagoras.

Baca juga: Kunci Jawaban Matematika Kelas 9 SMP, Halaman 214 Latihan Soal 4.1 Nomor 6, 7, 8 dan 9

Baca juga: Kunci Jawaban Dan Soal Pendidikan Kewarganegaraan PKN Semester 2 Kelas 9 Hal 98

Inilah Soal dan Kunci Jawaban Matematika Kelas 8 Semester 2 Halaman 29.

p = 2 dan q = 1

p⊃2; + q⊃2; = 2⊃2; + 1⊃2; = 4 + 1 = 5
p⊃2; – q⊃2; = 2⊃2; – 1⊃2; = 4 – 1 = 3
2pq = 2 × 2 × 1 = 4
Hubungan: 5⊃2; = 3⊃2; + 4⊃2;
Triple Pythagoras: 5, 3, 4
p = 3 dan q = 1

p⊃2; + q⊃2; = 3⊃2; + 1⊃2; = 9 + 1 = 10
p⊃2; – q⊃2; = 3⊃2; – 1⊃2; = 9 – 1 = 8
2pq = 2 × 3 × 1 = 6
Hubungan: 10⊃2; = 8⊃2; + 6⊃2;
Triple Pythagoras: 10, 8, 6
p = 3 dan q = 2

p⊃2; + q⊃2; = 3⊃2; + 2⊃2; = 9 + 4 = 13
p⊃2; – q⊃2; = 3⊃2; – 2⊃2; = 9 – 4 = 5
2pq = 2 × 3 × 2 = 12
Hubungan: 13⊃2; = 5⊃2; + 12⊃2;
Triple Pythagoras: 13, 5, 12
p = 4 dan q = 1

p⊃2; + q⊃2; = 4⊃2; + 1⊃2; = 16 + 1 = 17
p⊃2; – q⊃2; = 4⊃2; – 1⊃2; = 16 – 1 = 15
2pq = 2 × 4 × 1 = 8
Hubungan: 17⊃2; = 15⊃2; + 8⊃2;
Triple Pythagoras: 17, 15, 8
p = 4 dan q = 2

p⊃2; + q⊃2; = 4⊃2; + 2⊃2; = 16 + 4 = 20
p⊃2; – q⊃2; = 4⊃2; – 2⊃2; = 16 – 4 = 12
2pq = 2 × 4 × 2 = 16
Hubungan: 20⊃2; = 12⊃2; + 16⊃2;
Triple Pythagoras: 20, 12, 16
p = 4 dan q = 3

p⊃2; + q⊃2; = 4⊃2; + 3⊃2; = 16 + 9 = 25
p⊃2; – q⊃2; = 4⊃2; – 3⊃2; = 16 – 9 = 7
2pq = 2 × 4 × 3 = 24
Hubungan: 25⊃2; = 7⊃2; + 24⊃2;
Triple Pythagoras: 25, 7, 24
p = 5 dan q = 1

p⊃2; + q⊃2; = 5⊃2; + 1⊃2; = 25 + 1 = 26
p⊃2; – q⊃2; = 5⊃2; – 1⊃2; = 25 – 1 = 24
2pq = 2 × 5 × 1 = 10
Hubungan: 26⊃2; = 24⊃2; + 10⊃2;
Triple Pythagoras: 26, 24, 10
p = 5 dan q = 2

p⊃2; + q⊃2; = 5⊃2; + 2⊃2; = 25 + 4 = 29
p⊃2; – q⊃2; = 5⊃2; – 2⊃2; = 25 – 4 = 21
2pq = 2 × 5 × 2 = 20
Hubungan: 29⊃2; = 21⊃2; + 20⊃2;
Triple Pythagoras: 29, 21, 20
p = 5 dan q = 3

p⊃2; + q⊃2; = 5⊃2; + 3⊃2; = 25 + 9 = 34
p⊃2; – q⊃2; = 5⊃2; – 3⊃2; = 25 – 9 = 16
2pq = 2 × 5 × 3 = 30
Hubungan: 34⊃2; = 16⊃2; + 30⊃2;
Triple Pythagoras: 34, 16, 30
p = 5 dan q = 4

p⊃2; + q⊃2; = 5⊃2; + 4⊃2; = 25 + 16 = 41
p⊃2; – q⊃2; = 5⊃2; – 4⊃2; = 25 – 16 = 9
2pq = 2 × 5 × 4 = 40
Hubungan: 41⊃2; = 9⊃2; + 40⊃2;
Triple Pythagoras: 41, 9, 40